Math, asked by myhtctwo02, 5 months ago

tahir travels twice as far as ahmed, but only one third as fast. ahmed starts at point x at noon on Monday and travels to point z, 300 km away, by 9:00 PM the same day. if Tahir starts 3 hrs later than ahmed, when will Tahir reach point z? ( assuming no stops were made)​

Answers

Answered by rusher78
0

Answer:

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Answered by k345815
0

Step-by-step explanation:

Let the distance be xkm

travelling at 10kmph ,arun will reach point A at 2pm

travelling at 15kmph ,arun will reach point A at 12 noon

Therefore, time taken when travelling at 10km time taken when travelling at 15km = 2hrs

x/10 - x/15 = 2

3x - 2x = 2 *30

x = 60

Time needed if travelled at 10kmph

60/10 = 6hrs

Therefore to reach at 1pm, his travelling time. must be (6.1) = 5hrs

Hense required speed = 60/5 = 12kmph

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