Question

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Answer 1

Step-by-step explanation:

let us simplify the given expression = (x2y – 1) × (3 – 2x2y) = x2y (3 – 2x2y) – 1 (3 – 2x2y) = 3x2y – 2x4y2 – 3 + 2x2y = 5x2y – 2x4y2 – 3 Let us substitute the given values x = – 1 and y = – 2, then = (x2y – 1) × (3 – 2x2y) = [(-1)2 (-2) – 1] × [3 – 2 (-1)2 (-2) = (-2 – 1) × (3 + 4) = -3 × 7 = -21 Now, = 5x2y – 2x4y2 – 3 = [-2 (-1)4 (-2)2 + 5 (-1)2 (2) – 3] = – 8 – 10 – 3 = -21Read more on Sarthaks.com - https://www.sarthaks.com/630141/find-the-following-products-and-verify-the-results-for-x-1-y-2-x-2y-1-3-2x-2y