Question

Tajmahal, the seventh wonder of the world, is made of white stone. This white stone contains the same substance ‘A’ that is present in chalk powder and limestone. It is turning yellow due to polluted air. If it is cleaned by an acidic cleaner, a gas ‘B’ is released, which when passed through a solution ‘C’, forms the same substance which is present in the white stone that was used to make Tajmahal. 23) The substance A is A. Ca3CO2    B. CaCO3    C. Ca(OH)2    D. CaSO4 24) Gas B is A. Hydrogen    B. Nitrogen    C. Chlorine     D. Carbon di oxide  25) Solution C is A. CaCl2    B. CaCO3    C. Ca(OH)2    D. CaSO4 26) What is the nature of the substance A?  A. Acidic     B. Basic     C. Neutral     D. None.​

Answer 1

Answer:

23. ca(OH)2

24. carbon di oxide

25.CaCo3

26. basic

Explanation:

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Answer 2

23. The substance A is Calcium carbonate ($\[CaC{O_3}\]$). Thus, the correct option is B.

24. Gas B is carbon dioxide ($\[C{O_2}\]$). Thus, the correct option is D.

25. Solution C is Calcium hydroxide ($\[Ca{(OH)_2}\]$). Thus, the correct option is C.

26. The nature of substance A is basic. Thus, the correct option is B.

Explanation:

Limestone, marbles, chalk powder, etc. consists of the same chemical, i.e. calcium carbonate ($\[CaC{O_3}\]$). Therefore, the substance 'A' is calcium carbonate.

• When calcium carbonate is treated with acids, it forms calcium salt, carbon dioxide and water.
• Therefore, if the marble of the Taj Mahal is cleaned by an acidic cleaner, it will release carbon dioxide gas. Thus, gas 'B' is carbon dioxide.

        $\[CaC{O_3} + 2HCl \to CaC{l_2} + C{O_2} + {H_2}O\]$

• Carbon dioxide gas when reacted with calcium hydroxide, forms calcium carbonate.

        $\[C{O_2} + Ca{(OH)_2} \to CaC{O_3} + {H_2}O\]$

• Therefore, the solution C through which the gas is passed must be calcium hydroxide.
• As calcium carbonate reacts with acids to form calcium salts, therefore, it is basic in nature.