Math, asked by Bismillah786, 11 months ago

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Evaluate (a) (1/2)^2 + (1/3)^2+ (1/4)^2 (b) [(4^2 )^6÷(4^3 )^2 ] ÷ [(2^2 )^5÷(2^2 )^2 ]

Answers

Answered by AJAYMAHICH
2
a). 1/4 + 1/9 + 1/16

=( 16*9 + 4*16 + 4*9 ) / 4*9*16

=( 144 + 64 + 36 ) / 36*16

= (244) / 36*16

= 244 / 576

= 0.42



b). ( 4^12 ÷ 4^6 ) ÷ ( 2^10 ÷ 2^4 )

= ( 4^6 ) ÷ ( 2^6)

= ( 2^12 ) ÷ ( 2^6)

= ( 2^6)

= 64
Answered by spinder
3
Hope it helps you.

thanks.
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