Question

take 2gr ba(OH)² in one test tube . 1 gr NH⁴CI add to the solution and mix with glass rod what happen?​

Answer 1

$\huge \orange{ \boxed{\huge \purple{ \boxed{\huge \green{ \boxed{\huge \red { \underline{{{ᴀ}}}} \huge \pink { \underline{{{ɴ}}}} \huge \purple { \underline{ \mathfrak{{{s}}}}} \huge \blue { \underline{{{ᴡ}}}} \huge \orange { \underline{{{ᴇ}}}} \huge \mathbb { \underline{{{ʀ}}}}}}}}}}$

The reaction between Barium hydroxide

[ Ba (OH)2] and Ammonium chloride

NH4Cl

is ᴀɴ EɴᴅᴏᴛʜᴇʀMɪᴄ Rᴇᴀᴄᴛɪᴏɴ

because when ɪᴛ ʀᴇᴀᴄᴛs.........

occurs, then the TEMPERATURE FALLS

GRADUALLY.

> Ba (OH)2 + 2 (NH4Cl) → BaCL2 + 2 NH3 + 2 H2O.