Question

take -3/2 p + q - r from 1/2p - 1/3 q -3/2 r
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Answer 1

The value of the subtraction is calculated as,

[(1/2)p−(1/3)q−(3/2)r]−[(−3/2)p+q−r]

=(1/2)p+(3/2)p−(1/3)q−q−(3/2)r+r

We get,

=[(3p+9p−2q−6q−9r+6r)/6]

On further calculation, we get

=2p−(4/3)q−(1/2)r

Hence, [(1/2)p−(1/3)q−(3/2)r]−[(−3/2)p+q−r]=2p−(4/3)q−(1/2)r