take a=5 ,b= -3 and c= 4 , verify that . ,(ii) b×c=c×a , (iii) a×(b×c)=(a×b)×c ,(iv) a×(b+c)=a×b+a×c , (v) a×(b-c) = a×b-a×c
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Answer:
ii) -12 =20
iii) -60= -60
iv) 5=5
v) -35=-35
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ii) b x c = c x a
= (-3) x 4 = 4 x 5
= (-12) = 20
Hence b x c = c x a is not equal
iii) a x (b x c) = (a x b) x c
= 5 x [(-3) x 4] = [5 x (-3)] x 4
= 5 x (-12) = (-15) x 4
= (-60) = (-60)
hence a x (b x c) = (a x b) x c are equal
iv) a x (b+c) = a x b + a x c
= 5 x [(-3) + 4] = [5 x (-3)] + [5 x 4]
= 5 x 1 = (-15) + 20
= 5 = 5
Hence both are equal
v) a x (b - c) = a x b - a x c
= 5 x [(-3) - 4] = [5 x (-3)] - [5 x 4]
= 5 x (-7) = (-15) - (20)
= (-35) = (-35)
Hence both are equal
= (-3) x 4 = 4 x 5
= (-12) = 20
Hence b x c = c x a is not equal
iii) a x (b x c) = (a x b) x c
= 5 x [(-3) x 4] = [5 x (-3)] x 4
= 5 x (-12) = (-15) x 4
= (-60) = (-60)
hence a x (b x c) = (a x b) x c are equal
iv) a x (b+c) = a x b + a x c
= 5 x [(-3) + 4] = [5 x (-3)] + [5 x 4]
= 5 x 1 = (-15) + 20
= 5 = 5
Hence both are equal
v) a x (b - c) = a x b - a x c
= 5 x [(-3) - 4] = [5 x (-3)] - [5 x 4]
= 5 x (-7) = (-15) - (20)
= (-35) = (-35)
Hence both are equal
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