Question

Take A=90° and B=45° to verify that:
Sin(A-B) = sinAcos - CosAsinB
Cos(A-B) = cosAcosB + sinAsinB​

Answer 1

Step-by-step explanation:

sin(a-b)=sinAcosB-cosAsinB

sin(90-45)=sin90cos45-cos90sin45

sin45=(1)(1/√2)-(0)(1/√2)

sin45=1/√2

Cos(A-B) = cosAcosB + sinAsinB

Cos(90-45)=cos90cos45+sin90sin45

cos45=(0)(1/√2)+(1)(1/√2)

cos45=1/√2

Answer 2

Step-by-step explanation:

here's your answer

hope it helped you