Question

Take a bright metal ball and make it black with soot in a candle flame. immerse it in water. how does it appear and why?

Answer 1

As the bright metal ball is made black with soot, air enters in  between space of the soot and the metal ball.

When the angle of incidence exceeds the critical angle then total internal reflection takes place and the ball with a soot coating appears bright.
In addition to this due to the refraction of light the ball to be raised high in its position

Answer 2

when the metal ball blackened with soot is kept immersed in water we can observe the surface of immersed portion appearing silver you to total internal reflection usually the soot is oily and pluffy contain air between its particles when we immerse it then the thin air layer will surfaces along the soot and make the light rays travel to undergo total internal reflection a until it becomes wet by absorbing water