Physics, asked by nwzrock, 1 year ago

take a hollow plastic ball (dia 3 cm to 5 cm) .using a needle pass thread of about 105 cm along a diameter of the ball .tie a knot at one end . hang the ball from a rigid support so that the ball is free to oscillate . make a small hole (5m dia) in the ball near the top . fill it with sand and find its time period of oscillation .empty the ball and fill it with steel balls /iron filings and repeat the experiment . similarly carry out the experience with common salt. compare the time periods obtained in the

Answers

Answered by Geekydude121
4
Answer- 
Is it related to the formula T = 2*pi*SQRT(m/k)? If yes, then between sand, iron filings, salt which will give larger time periods? 
I think Salt is denser than sand and obviously, iron filings are heavier than both. SO according to the equation, T is directly proportional to sqrt m. So iron fillings will give larger time period.

You will find the same oscillation periods for each filling you use because the period depends only on the length of the pendulum, and the value of g.


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