take a line segment PQ draw a perpendicular bisector of PQ . Take a point m on the perpendicular bisector . Prove that m is equidistance from P and Q?
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Step-by-step explanation:
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Steps of Construction :
1. With P and Q as centers, draw arcs on both sides of PQ with equal radii. The radius should be more than half the length of PQ.
2. Let these arcs cut each other at points R and RS
3. Join RS which cuts PQ at D. Then RS=PQ. Also ∠POR=90
∘
.
Hence, the line segment RS is the perpendicular bisector of PQ as it bisects PQ at P and is also perpendicular to PQ. On measuring the lengths of PR=4cm, QR=4 cm Since PR=QR, both are 4cm each
∴PR=QR.
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