Question

Take a point P above a straight line AB. Through P draw a straight line PQ perpendicular to AB.​

Answer 1

Answer:

let line AB be ax+by+c=0

Step-by-step explanation:

hence it's slope is -a/b

for perpendicular lines m×M=-1

So slope of perpendicular line is b/a.

line will be bx-ay+k=0

for value of k pass this line from point p.

thanks.