Question

take a small amount of copper oxide in a beaker and add dilute hydrochloric acid slowly while staring not the colour of the solution what has happened to the copper oxide and write the equation

Answer 1

CuO + HCl → CuCl2 + H2O

The colour of the solution will change to blue-green due to the formation of copper chloride.

Copper oxide has changed to copper chloride.

Answer 2

Hii Dixi,

● Answer -
Colour of solution changes to bluish-green due to CuCl2 formation.
CuO(aq) + HCl(l) → CuCl2(aq) + H2O(l)

● Explaination -
Copper oxide reacts with hydrochloric acid to form copper chloride & water.
CuO(aq) + HCl(l) → CuCl2(aq) + H2O(l)


This CuCl2 formed changes solution to blueish green color.




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Thanks for asking..