Take a thick paper sheet of length 14cm and
width 9cm. Find its Area and Perimeter. Then
cut strips of equal sizes out of it. Using tape
join the strips, end to end, to make a belt.
Find length of belt and also find its perimeter.
Answers
Ans. (a) We know that,
Area of a rectangle = Length * Breadth
Area of a thick paper sheet = (Length * Breadth)
= (14*9) square cm = 126 square cm
Perimeter of a rectangular sheet
= 2(Length+ Breadth)
= 2(14 + 9) cm
= 2 * 23 cm = 46cm
(b) Let us cut strips of equal sizes out of the given paper sheet of length 14 cm and width 9 cm.
(c) Strips having width 1 cm:
There will be 9 strips of width 1 cm and length 14 cm. Let us join these strips end to end using tape to make a belt.
Its length
= (14+14+14+14+14+14+14+14+14)
= 9 * 14 cm = 126 cm
It’s perimeter = 2(126+1) cm = 2 127 cm = 254 cm
(d) Strips having length 1.5 cm:
There will be 6 strips of width 1.5 cm and length 14 cm. Let us join these strips end to end using tape to make a belt.
It’s length = (14+14+14+14+14+14) cm
= 6 * 14 cm = 84 cm
It’s perimeter = 2 (84 + 1.5) cm = 2* 85 – 5 cm = 171 cm
(e) Whose belt is the longest in the class?
Ans. (e) Strips having width 3 cm:
There will be 3 strips of width 3 cm and length 14 cm.
Let us join these strips end to end using tape to make a belt.
It’s length = (14+14+14) cm = 3 * 14 cm = 42 cm
It’s perimeter = 2(42+3) cm = 2 * 45 cm = 90 cm
Clearly, the belt with shortest width is the longest one. Thus, the belt having width 1 cm is the longest in the class.
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
FIRSTLY WE ARE GOING TO FIND THE ARE AND ITS PERIMETER SO,
PERIMETER OF A TRIANGLE =2(L+B)
2(14+9)
2×23
=45
AREA IF A TRIANGLE =L×B
14×9
=126
SO,WE KNOW THAT L=14 AND B=9
WE ARE CUTTING IN 2 PIECES SO
14/2=7 AND 9/2=4.5
AND NOW WE ARE GOING TO JOIN THE ENDS OF THE BELT SO
7+7=14 and 4.5 WILL REMAIN AS USUAL
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