Question

Take a wire of length 36 cms. Bend it in the shape of equilateral△. Find area of triangle formed. Now bend the same wire in the shape of a square. Find area of square formed. Which of these areas is more ?

Answer 1

Answer:

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Step-by-step explanation:

Perimeter of the equilateral triangle = 3s

                                                       36 = 3s

                                                          s = 12cm

Area = $\sqrt{3}/4 * 12^{2}$

        = 62.35383$cm^{2}$

Perimeter of the square = 36

                                   36 = 4s

                                      s = 9cm

Area = $s^{2}$

        = $9^{2}$

        = 81$cm^{2}$

Therefore, the area of the square is greater than the area than than the area of the triangle.