Take any point O in the interior of a triangle PQR . is OP+QQ >PQ
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yes. As, OPQ forms another triangle in PQR,..
as per the rule for formation of triangles,
length of a side of a triangle < sum of the other two sides,
In triangle OPQ,
OQ<PQ+OP
OP<PQ+OQ
hence, PQ<OP+OQ
as per the rule for formation of triangles,
length of a side of a triangle < sum of the other two sides,
In triangle OPQ,
OQ<PQ+OP
OP<PQ+OQ
hence, PQ<OP+OQ
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Answered by
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If O is a point in the interior of a given triangle, then three triangles ΔOPQ, ΔOQR, and ΔORP can be constructed. In a triangle, the sum of the lengths of either two sides is always greater than the third side.
(i) Yes, as ΔOPQ is a triangle with sides OP, OQ, and PQ.
OP + OQ > PQ
(ii) Yes, as ΔOQR is a triangle with sides OR, OQ, and QR.
OQ + OR > QR
(iii) Yes, as ΔORP is a triangle with sides OR, OP, and PR.
OR + OP > PR
(i) Yes, as ΔOPQ is a triangle with sides OP, OQ, and PQ.
OP + OQ > PQ
(ii) Yes, as ΔOQR is a triangle with sides OR, OQ, and QR.
OQ + OR > QR
(iii) Yes, as ΔORP is a triangle with sides OR, OP, and PR.
OR + OP > PR
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