take any two linear equations in one variable and find the variable value by using transportation method
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Step-by-step explanation:
Let’s Begin with an Example
Example 1: Solve
x
2
−
x
3
=
8
Solution: we have,
x
2
−
x
3
=
8
LCM of denominators 2 and 3 on L.H.S. is 6. So,
3
x
−
2
x
6
=
8
Multiplying both sides by 6, we get
3
x
−
2
x
=
6
×
8
x
=
48
Check Substituting x=48 in the given equation, we get
L
H
S
=
48
2
−
48
3
L
H
S
=
24
−
16
L
H
S
=
8
Therefore L.H.S. =R.H.S. Hence, x =48 is the solution of the given equation
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