Take away −3x cube +4xsq -5x +6 from the sum of −3x cube +4xsq -5x +6 and 4x cube -8xsq +15
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Correct Question:
Take away −3x³ +4xsq -5x +6 from the sum of −3x³ +4xsq -5x +6 and 4x³ -8xsq +15
Solution:
→ First, we have to add the algebraic expressions −3x³ +4xsq -5x +6 and 4x³ -8xsq +15.
= −3x³ +4xsq -5x +6 + 4x³ -8xsq +15
= x³ - 4xsq - 5x + 21
→ Now, we have to subtract −3x³ +4xsq -5x +6 from this answer.
= x³ - 4xsq - 5x + 21 - (−3x³ +4xsq -5x +6)
= x³ - 4xsq - 5x + 21 + 3x³ - 4xsq + 5x - 6
= 4x³ - 8xsq + 15
Therefore when we take away −3x³ +4xsq -5x +6 from the sum of −3x³ +4xsq -5x +6 and 4x³ -8xsq +15, we get 4x³ - 8xsq + 15.
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