Question

take away 8/5t³ - 3/2t + 1/5t² - 1 from 1/5t³ - 5/2t + 1/3t² - 4.​

Answer 1

Answer:

Given displacement x=5+3t+2t

2

Differentiating the above equation with respect to time t we get velocity of the body

v=

dt

dx

=3+4t

Now again differentiating the velocity with respect to time we get acceleration

a=

dt

dv

=4