Question

Take lead nitrate solution in a test tube add potassium iodide solution to this what do you observe

Answer 1

We will observe an yellow precipitate of Pead iodide (PbI2) along with KNO3.

Pb(NO3)2 + 2KI -------> 2KNO3 + PbI2

Answer 2

Answer: This leads to the formation of a yellow precipitate of lead iodide.

Explanation:

When lead nitrate is reacted with potassium iodide, it produces lead iodide and potassium nitrate. The reaction between the two is known as double displacement and precipitation reaction.

A yellow precipitate of lead iodide is formed in the reaction. The chemical equation following the above reaction is:

$Pb(NO_3)_2(aq.)+2KI(aq.)\rightarrow PbI_2(s)+2KNO_3(aq.)$

By Stoichiometry of the reaction:

1 mole of lead nitrate reacts with 2 moles of potassium iodide to produce 1 mole of lead iodide and 2 moles of potassium nitrate.