Question

Take lead nitrate
solution in a test
tube.
Add potassium
iodide solution
to this.
WRITE THE:-
a) Aim of the activity b) Materials required
c) Procedure d) Observation & result.

Answer 1

Answer:

Answer: This leads to the formation of a yellow precipitate of lead iodide.

Explanation:

When lead nitrate is reacted with potassium iodide, it produces lead iodide and potassium nitrate. The reaction between the two is known as double displacement and precipitation reaction.

A yellow precipitate of lead iodide is formed in the reaction. The chemical equation following the above reaction is:

Pb(NO_3)_2(aq.)+2KI(aq.)\rightarrow PbI_2(s)+2KNO_3(aq.)Pb(NO

3

)

2

(aq.)+2KI(aq.)→PbI

2

(s)+2KNO

3

(aq.)

By Stoichiometry of the reaction:

1 mole of lead nitrate reacts with 2 moles of potassium iodide to produce 1 mole of lead iodide and 2 moles of potassium nitrate.

Explanation:

hope you have understood that