Question

Take lead nitrate solution in a test tube. Add potassium iodide solution to this, What do you observe?

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Answer 1

Answer:

Acetic acid is first converted to its calcium salt by neutralising it with quick lime.

Acetic acid is first converted to its calcium salt by neutralising it with quick lime.2CH3COOH + CaO = Ca(CH3COO)2 + H2O

Acetic acid is first converted to its calcium salt by neutralising it with quick lime.2CH3COOH + CaO = Ca(CH3COO)2 + H2OSolid (pure) calcium acetate on dry distillation yields acetone by decomposition.

Acetic acid is first converted to its calcium salt by neutralising it with quick lime.2CH3COOH + CaO = Ca(CH3COO)2 + H2OSolid (pure) calcium acetate on dry distillation yields acetone by decomposition.Ca(CH3COO)2 = CH3COCH3 + CaCO3

Acetic acid is first converted to its calcium salt by neutralising it with quick lime.2CH3COOH + CaO = Ca(CH3COO)2 + H2OSolid (pure) calcium acetate on dry distillation yields acetone by decomposition.Ca(CH3COO)2 = CH3COCH3 + CaCO3Acetone is usually prepared in the laboratory by the dry distillation of calcium acetate.

Explanation:

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Answer 2

Answer:

When we add lead nitrate solution in potassium iodide solution , potassium nitrate is formed along with lead iodide with yellow golden precipitate .

This Chemical Reaction is an example of Double Displacement Reaction , which is as :

Pb(No3)2 + 2kI ➝ Pbl2 + 2KNo3