Question

Take the molar volume to be 24 dm (24,000 cm) at rtp.
(RAMS: O = 16; CI = 35.5)
a) Calculate the mass of 200 cm3 of chlorine gas (Cl2) at rtp.
b) Calculate the volume occupied by 0.16 g of oxygen (O2) at rtp.
c) If 1 dm of a gas at rtp weighs 1.42 g, calculate the mass of 1
mole of the gas.​

Answer 1

Answer:

The ideal gas equation relating pressure (P), volume (V), and absolute temperature (T) is given as:

PV = nRT

Where,

R is the universal gas constant =8.314Jmol

−1

K

−1

n = Number of moles = 1

T = Standard temperature = 273 K

P = Standard pressure = 1 atm =1.013×10

5

Nm

−2

∴V=nRT/P

=1×8.314×273/(1.013×10

5

)

=0.0224m

3

=22.4 litres

Hence, the molar volume of a gas at STP is 22.4 litres.