take the perimeter of a recttangular board is 70 cm. taking its length as x cm find its width . and the area of the board is 300 cm sq find the dimensions
Answers
Answered by
0
Perimeter of rectangle 2(l+b)
2(l+b) = 70
X+b=35
B=35-x
Area of rectangle = l×b
L×b= 300
X(35-x) =300
35x-x^2 =300
35-x^2-300 =0
Take minus common and divide it with 0.u will get the quadratic equations i. e
X^2-35+300=0
X^2-20x-15x+300=0
Take common
So u will get
X-20=0or x-15=0
X=20 or 15
Substitute those value in 35 -b to find the value of breadth
2(l+b) = 70
X+b=35
B=35-x
Area of rectangle = l×b
L×b= 300
X(35-x) =300
35x-x^2 =300
35-x^2-300 =0
Take minus common and divide it with 0.u will get the quadratic equations i. e
X^2-35+300=0
X^2-20x-15x+300=0
Take common
So u will get
X-20=0or x-15=0
X=20 or 15
Substitute those value in 35 -b to find the value of breadth
Similar questions