Question

Take the solutions of CuSO4, ZnSO4, FeSO4 and MgSO4 in four separate beakers. Add Fe nail in
and II, Cu turning in III and IV, and write your observations.​

Answer 1

Answer:

(i) B is the most reactive metal as it has displaced the most reactive metal amongst the solutions i.e Fe of FeSO

4

.

(ii) If B is added to CuSO

4

solution than it will displace Cu because Fe is more reactive than Cu so the metal which can displace Fe can also displace Cu.

(iii) D < C < A < B.

(iv) Metal D can be used to make containers to store the solutions because it is the least reactive metal of all.

Answer 2

$\bold{CuSO_4 ,ZnSO_4 ,FeSO_4 \: and \: MgSO_4}$

are 1st, 2nd, 3rd and 4th beakers respectively.

Now,

Fe nail in 1st,

Fe is less reactive than copper, so iron will displace copper from its salt solution and forms iron sulphate.

Now,

Cu in 3rd and 4th.

Since copper is less reactive than zinc and magnesium, adding copper in the because would not affect the reaction and that's why no reaction will take place. Which results in formation of no new compound.