take the values as x and y
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mornin mate!....
let the age of father be x and that of his son be y...
then
x=6y.......(I)
and four years later ,
(x+4)= 4(y+4)
x+4= 4y +16
substituting x=6y
6y+4=4y+16
2y=12
y=6
therefore ...x=36
here's ur answer....
thank u!
let the age of father be x and that of his son be y...
then
x=6y.......(I)
and four years later ,
(x+4)= 4(y+4)
x+4= 4y +16
substituting x=6y
6y+4=4y+16
2y=12
y=6
therefore ...x=36
here's ur answer....
thank u!
Answered by
0
Let father's age be x and son's age be y.
x=6y
(x+4)=4(y+4)
Now put the value of x=6y then,
6y+4=4y+16
2y=12
y=6
So x=36
x=6y
(x+4)=4(y+4)
Now put the value of x=6y then,
6y+4=4y+16
2y=12
y=6
So x=36
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