Math, asked by riya4459, 8 months ago

take three coins of different denomination you have to toss these coins as the same time. Write the sample space for the event and find the probability of getting:
1) two heads
2) atleast one tail
3) atmost one head
4) atleast two tails ​

Answers

Answered by parvatha91
2

Step-by-step explanation:

In tossing three coins, the sample space is given by

{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

(a) Then all possible outcomes are =8

(b) Then number of possible outcomes=8

(c)Then the probability of getting at least one head=

numberoftotalpossibleoutcomes

numberofpossibleoutcomesofoneheads

=

8

3

(d)Then the probability of getting at least two heads=

numberoftotalpossibleoutcomes

numberofpossibleoutcomesoftwoheads

=

8

3

(e)Then the probability of getting no tail=

numberoftotalpossibleoutcomes

numberofpossibleoutcomesofnotail

=

8

1

Answered by amitnrw
3

Given : Take three coins of different denomination. Toss these coins simultaneously and there are 8 possible outcomes

To find : probability of getting:

1) two heads

2) atleast one tail

3) atmost one head

4) atleast two tails  

Solution:

Tossing 3 coins simultaneously

S ={ (HHH) , (HHT) , (HTH), (HTT) ,  (THH) , (THT) , (TTH), (TTT)}

n(S) = 8

getting 2 heads = {(HHT) , (HTH),  (THH)  }

n(getting 2 heads) = 3

The probability of getting 2 heads  = 3/8

atleast one tail =  {  (HHT) , (HTH), (HTT) ,  (THH) , (THT) , (TTH), (TTT)}

n( atleast one tail)  = 7

The probability of getting atleast one tail  = 7/8

atmost one head = { (HTT) ,   (THT) , (TTH), (TTT)}

n (atmost one head) = 4

 The probability of getting atmost one head = 4/8 = 1/2

atleast two tails ​ = {  (HTT) ,   (THT) , (TTH), (TTT)}

n (atleast two tails) = 4

 The probability of getting atleast two tails = 4/8 = 1/2

 

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