take three coins of different denomination you have to toss these coins as the same time. Write the sample space for the event and find the probability of getting:
1) two heads
2) atleast one tail
3) atmost one head
4) atleast two tails
Answers
Step-by-step explanation:
In tossing three coins, the sample space is given by
{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
(a) Then all possible outcomes are =8
(b) Then number of possible outcomes=8
(c)Then the probability of getting at least one head=
numberoftotalpossibleoutcomes
numberofpossibleoutcomesofoneheads
=
8
3
(d)Then the probability of getting at least two heads=
numberoftotalpossibleoutcomes
numberofpossibleoutcomesoftwoheads
=
8
3
(e)Then the probability of getting no tail=
numberoftotalpossibleoutcomes
numberofpossibleoutcomesofnotail
=
8
1
Given : Take three coins of different denomination. Toss these coins simultaneously and there are 8 possible outcomes
To find : probability of getting:
1) two heads
2) atleast one tail
3) atmost one head
4) atleast two tails
Solution:
Tossing 3 coins simultaneously
S ={ (HHH) , (HHT) , (HTH), (HTT) , (THH) , (THT) , (TTH), (TTT)}
n(S) = 8
getting 2 heads = {(HHT) , (HTH), (THH) }
n(getting 2 heads) = 3
The probability of getting 2 heads = 3/8
atleast one tail = { (HHT) , (HTH), (HTT) , (THH) , (THT) , (TTH), (TTT)}
n( atleast one tail) = 7
The probability of getting atleast one tail = 7/8
atmost one head = { (HTT) , (THT) , (TTH), (TTT)}
n (atmost one head) = 4
The probability of getting atmost one head = 4/8 = 1/2
atleast two tails = { (HTT) , (THT) , (TTH), (TTT)}
n (atleast two tails) = 4
The probability of getting atleast two tails = 4/8 = 1/2
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