Take three glass bottles with wide mouths. Label them A, B and C. Fill about half of bottle A with ordinary tap water. Fill bottle B with water which has been boiled for several minutes, to the same level as in A. In bottle C, take the same boiled water and of the same amount as in other bottles. In each bottle put a few similar iron nails so that they are completely under water. Add a teaspoonful of cooking oil to the water in bottle C so that it forms a film on its surface. Put the bottles away for a few days. Take out nails from each bottle and observe them. Explain your observations.
Answers
Answer:
The nails in bottle B form a little rust, nails in A are fully rusted and nails in C are not rusted.
Explanation:
Rusting is a reaction. In this process, the iron reacts with water and oxygen present in the surroundings to form rust.
In bottle A, both oxygen and water are present which are responsible for rusting. Oxygen is present in the dissolved form in water.
Therefore, the nails in bottle A are fully rusted.
In Bottle B, since the water is boiled, the dissolved air in the water is removed. In this, as there is no oxygen present iron nails do not rust much.
In bottle C, Both boiled water and oil is added into the water. These two factors prevent the dissolving of atmospheric air in water.
Hence, The nails in bottle C do not rust
Therefore, the nails in bottle B form a little rust, nails in A are fully rusted and nails in C are not rusted at all i.e, they remained unchanged.
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