take three test tubes. fill 3/4 of each with water. label them a,b,and c ,keep snail in test tube a, a water plant in test tube b and in c keep snail and plant both which test tube would have the highest concentration of co2
Answers
Answer:
In plants body basic structure is a major criteria based on which Thallophytes are different from Bryophytes. Apart from this absence or presence of seeds is another important criteria. Gymnosperms and angiosperms are further segregated based on if seeds are covered or not. It is clear that it is the morphological character which makes the basis for classification of plants.
In animals classification is based on more minute structural variations. So in place of morphology, cytology forms the basis. Animals are classified based on layers of cells, presence or absence of coelom. Further higher the hierarchy animals are classified based on presence or absence of smaller features, like presence or absence of four legs.
Answer:
The test tube A will have the highest concentration of carbon dioxide. The carbon dioxide(CO
2
) comes because of respiration by the snail. Snail is an organism that breaths in O
2
and breaths out (CO
2
).Hence,(CO
2
concentration increases in test tube A.
The test tube B contains a water plant, which takes is (CO
2
) for photosynthesis and gives out O
2
.Hence, more O
2
concentration is seen in test tube B.
The test tube C contains both snail and a water plant. The CO
2
) produced by the snail is utilized by the plant for the photosynthesis and the O
2
released by the plant is utilized for snails respiration.
Therefore The test tube A will have the highest concentration of carbon dioxide.