Take two consecutive odd numbers. Find the sum of their squares,and then add 6 to the result. Prove that the new number is always divisible by 8.
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I have taken 2n+1 and 2n-1 as odd numbers
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two consecutive odd numbers be 1 and 3
then there squares would be 1 and 9
=1+9= 10
add 6 to the result
10+6=16
divide by 8
16\8= 4
hence proved that the new number is divisible by8
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