Question

take wires of the same materials but of two different diameters and find the value of L for each of these for a given frequency n and tension

Answer 1

Explanation:

from wire 1, A

1

=πD

2

from wire 2, A

2

=4πD

2

the mean drift velocity ∝

area

1

V

drift

∝

Area

1

V

2

V

1

=

A

2

A

1

=

4πD

2

πD

2

V

2

V

1

=

4

1

Answer 2

Answer:

Therefore, The ratio of the mean drift velocity is 4: 1.

Explanation:

It is the average speed that an electric field causes a charged particle (such as an electron or proton) to acquire within a body. The average velocity is typically zero since an electron within a conductor flows haphazardly at the Fermi velocity.

There is no electric field. When an electric field is present, all of the electrons first move at random speeds and directions, but eventually acquire an average speed and move in the opposite direction of the applied field. This average speed is known as drift velocity.

From wire 1, $A_{1}$ = $\pi D^{2}$

from wire 2,

$A_{2}$ = $\pi D^{2} /4 = \pi D^{2}$

The mean drift velocity is directly proportional to the Area.

The mean drift velocity ∝ $\frac{1}{Area}$

So, $V_{dirft} = \frac{1}{Area}$

Now, we can write as,

$\frac{V_{1} }{V_{2} } =\frac{A_{1} }{A_{2} } =\frac{\pi D^{2} }{\pi D^{2}/4 } =\frac{4}{1}$

Therefore, The ratio of the mean drift velocity is 4: 1.

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