taking √2 = 1.414 and √3 = 1.732, find without using tables aur long division the value of 1/ 3- √2
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{ 4/(3√3–2√2)}+{ 3/(3√3+2√2)}=?
={4×(3√3+2√2)+3×(3√3–2√2)}/(3√3–2√2).(3√3+2√2).
={12√3+8√2+9√3–6√2}/(27–8).
=(21√3+2√2)/19.
=(21×1.732+2×1.414)/19.
=(36.372+2.828)/19.
=39.200/19
=2.063. Answer.
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