Question

Taking θ =30°. Verify that sin3θ=3sinθ-4sin³θ

pls say fast.. ​

Answer 1

Step-by-step explanation:

Now, LHS=sin3(30

o

)=sin90

o

=1

Now, RHS=3sinθ−4sin

3

θ=3sin30

o

−4sin

3

30

o

=3(

2

1

)−4(

2

1

)

3

=

2

3

−

2

1

=1

∴ LHS=RHS

Hence proved