Math, asked by soyabbhatta87, 11 months ago

taking any measure of an acute angles for angle A prove that sin2A = 2sinA.cosA​

Answers

Answered by pritamdas77
0

Answer:

sin2A= sin (A+A)

= sinAcosA + CosAsinA (because we know

=2sinAcosA that sin(A+B)= sinAcosB + CosAsinB)

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