Question

Taking the mass of earth as 6.4×10²⁴m, Calculate the value of acceleration due to gravity at a height of 2000 km above the surface of Earth?​

Answer 1

Given :-

Mass of earth = 6.4 × 10²⁴

Height from surface of earth = 2000 km

To Find :-

The acceleration due to gravity

Solution :-

we know that,

$\sf g = \dfrac{Gm}{r^{2}}$

here,

• g = acceleration due to gravity;
• G = Universal Gravitational Constant
• r = distance

$\sf g = \dfrac{6.67 × 10^{-11} × 6.4 × 10^{24}}{2000^{2}}$

$\sf </p><p>g = \dfrac{6.67 × 6.4 × 10^{13}}{4 × 10^{6}}$

$\sf </p><p>g = \dfrac{6.67 × 1.6 × 10^{13}}{10^{6}}$

thus, the acceleration due to gravity is $\sf \dfrac{6.67 × 1.6 × 10^{13}}{10^{6}}$

$\:$

#sanvi....

Answer 2

Answer:

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