taking theta = 30 degree ,cos 2 theta
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0
Answer:
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Answered by
0
Answer:
cos2θ=
1+tan
2
θ
1−tan
2
θ
cos2(30
∘
)=
1+tan
2
30
∘
1−tan
2
30
∘
cos60
∘
=
1+tan
2
30
∘
1−tan
2
30
∘
2
1
=
1+(
3
1
)
2
1−(
3
1
)
2
2
1
=
3+1
3−1
2
1
=
4
2
2
1
=
2
1
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