Question

Taking 'x', 'y' as variables and 'k' as a constant, if x = 2y and y + k = 11 and x - 2k = -18, then the value of (x+y)
is? Answer with explain

Answer 1

Answer:

x = 2y

y = x/2........(i)

y + k = 11

x/2 + k = 11

(x + 2k)/2 = 11

x + 2k = 22

2k = 22 - x

x - 2k = -18

x - 22 + x = -18........[ 2k = 22 - 2k ]

x + x = -18 + 22

2x = 4

x = 4/2

x = 2..........(ii)

(i) ..... y = x/2

....... y = 2/2.......[ x = 2 ]

....... y = 1

then..... x + y = 2 +1 = 3

Step-by-step explanation:

....✌✌✌✌✌✌✌

Answer 2

$\large{\underline{\underline{\mathfrak{\green{\sf{Solution:-}}}}}}$.

$\implies\:(x+y)\:=\:30$

$\large{\underline{\underline{\mathfrak{\green{\sf{Given\:equation :-}}}}}}$.

• $\:(x-2y)\:=\:0$....(1)

• $\:(y+k)\:=\:11$....(2)

• $\:(x-2k)\:=\:18$.....(3)

$\large{\underline{\underline{\mathfrak{\green{\sf{Find\:here:-}}}}}}$.

• Value of x and y

$\large{\underline{\underline{\mathfrak{\sf{Explanation:-}}}}}$.

By, equation (2) ,

$\implies\:(y\:=\:11-k)$.......(4)

Keep value of y in equation (1). ,

$\implies\:x-2(11-k)\:=\:0$

$\implies\:x+2k\:=\:22$......(5)

Now, Solve equation (3) and (5)

Addition of equation (3)+(5), will be

$\implies\boxed{\:x\:=\:20}$

Now, keep value of x in equation (5),

$\implies\:20+2k\:=\:22$

$\implies\:2k\:=\:(22-20)$

$\implies\:k\:=\frac{2}{2}$

$\implies\boxed{\:k\:=\:1}$.........(6)

Now, keep value of k , in equation (4)

$\implies\:y\:=\:(11-1)$

$\implies\boxed{\:y\:=\:10}$

Now, Value of (x+y),

$\implies\:(x+y)\:=\:(20+10)$

$\implies\boxed{\boxed{\:(x+y)\:=\:30}}$

_______________________