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A door of length 4 m and breadth 3 m is fitted in a wall. The length of the wall is 16 m
and the breadth of the wall is 13 m 9 cm. Find the cost of whitewashing the wall at the
rate of 20 per square metre.
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Answer:
Your solution:
Given,
Length of Door= 4m & Breadth of Door= 3m
Therefore,
Area of Door= L×B = 4m×3m = 12m^2
Given,
Length of Wall= 16m & Breadth of Wall= 13.9m
Therefore,
Area of wall= L×B = 16m× 13.9m = 222.4 m^2
Area required for whitewashing
= Area of wall - Area of door
= (222.4 - 12) m^2
= 210.4 m^2
Cost for whitewashing per square metre
= 20 × Area required for whitewashing
= (20 × 210.4) rupees
= 4,208 rupees.
Hope this helps..
Mark Brainliest ♡♡♡
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