Question

tan 0=√3,then sec 0=​

Answer 1

Trigonometric identity

sec${}^{2}$θ−tan${}^{2}$ θ=1

∴sec${}^{2}$ θ = 1+tan${}^{2}$θ= 1+(√3 )${}^{2}$ = 1+3=4

$⇒$sec θ=2.

Answer 2

$\huge\underbrace\bold\red{ Answer }$

$Trigonometric \: \: identity$

$sec{}^{2} \: 2 θ−tan{}^{2} \: 2 θ=1$

$∴sec{}^{2}2 θ = 1+tan{}^{2}2 θ= \\ \\ 1+(√3 ){}^{2}2= 1+3=4$

$⇒ sec θ=2.$