Question

tan 0 + tan (90° – 0) = sec 0 sec (90° - 0)​

Answer 1

answer is given in the picture :)

Answer 2

Answer:

Step-by-step explanation:

tanθ  + tan(90- θ)

tan θ +cot θ

sin θ/cos θ + cos θ/sin θ

=(sin² θ + cos² θ)/sin θcos θ

=1/sin θcos θ

=cosec θ+sec θ

sec(90- θ) + sec θ

∴sec(90- θ)= cosec  θ

i hope you got the answer you are searching for dear..