tan 0 + tan (90° – 0) = sec 0 sec (90° - 0)
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answer is given in the picture :)
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Step-by-step explanation:
tanθ + tan(90- θ)
tan θ +cot θ
sin θ/cos θ + cos θ/sin θ
=(sin² θ + cos² θ)/sin θcos θ
=1/sin θcos θ
=cosec θ+sec θ
sec(90- θ) + sec θ
∴sec(90- θ)= cosec θ
i hope you got the answer you are searching for dear..
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