Question

tan 0 + tan (90° - 0) = sec 0 sec (90° - 0)​

Answer 1

Answer:

$\tan(0) = 0$

$\tan(90 - 0) = \cot(90)$

$\\ \sec(0) = 1$

$\sec(90 - 0) = \cos(90)$

$\bf{substitute \: values \: }$

$0 + 0 =1 \times (0)$

$\therefore \: hence \: proved$

$\therefore \huge{\: mark \: me \: brainliest} \therefore$