Question

tan^-1(1)+cos^-1 (-1/2) + sin^-1(-1/2)

Answer 1

${ \tan}^{ - 1} (1) + { \cos}^{ - 1} ( - \frac{1}{2} ) + { \sin }^{ - 1} ( - \frac{1}{2} ) \\ \\ = \frac{\pi}{4} + \frac{2\pi}{3} + \frac{5\pi}{6} \\ \\ = \frac{3\pi + 8\pi + 10\pi }{12} \\ \\ = \frac{21\pi}{12} \\ \\ = \frac{7\pi}{4}$