Question

tan^-1[✓1-cosx/1+cosx]=x/2
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Answer 1

Answer:

Take = cosx=1+tan2x/21−tan2x/2

1+cosx1−cosx=1+1+tan2x/21−tan2x/21−1+tan2x/21−tan2x/2

=1+tan2x/2+1−tan2x/21+tan2x/2−1+tan2x/2

=22tan2x/2=tan2x/2

1+cosx1−cosx=tan2x/2=tanx/2

Now, tan−1[tan(2x)]=2

Step-by-step explanation:

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