tan^-1[(√1+x)-(√1-x)/(√1+x)+(√1+x)]=π/4-1/2जहा -1/2≤x≤1
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The number of values of x∈[0,4π] satisfying
∣
∣
∣
3
cosx−sinx
∣
∣
∣
≥2 is
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ANSWER
given, ∣
3
cosx−sinx∣≥2
⇒∣cos
6
π
cosx−cos
6
π
sinx∣≥1
⇒∣cos(x+
6
π
)∣≥1
but we know ∣cos(x+
6
π
)∣≤1
Hence,
⇒∣cos(x+
6
π
)∣=1⇒cos(x+
6
π
)=±1
Hence solutions in the given interval are,
x=
4
3π
,
4
7π
,
4
11π
,
4
15π
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