tan^-1(2) +tan^-1(3)= ?
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Answer:
tan^-1(1)=π/4
Step-by-step explanation:
tan^-1(1/2)+tan^-1(1/3)
tan^-1(1/2+1/3)/1-1/2*1/3
tan^-1(3+2/6)/1-1/6
tan^-1(5/6)/6-1/6
tan^-1(5/6*6/5)
tan^-(1)=π/4
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