Math, asked by dakshvashishta7317, 9 months ago

tan^-1[2cos(2sin^-11/2)]

Answers

Answered by hanshu1234

0

Step-by-step explanation:

The value of tan−1[2cos(2sin−121)]

=tan−1[2cos(2⋅6π)]

=tan−1[2cos(3π)]

=tan−1[2⋅21]

=tan−11

=4π

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