Question

tan-1 (2x/1-x2)+ cot-1(1-x2/2x)=180/3,-1

Answer 1

tan−1(2x1−x2) +cot−1(1−x22x) 

=π3As tan−1x

 =cot−11xSo  tan−1(2x1−x2) +tan−1(2x1−x2) 

=π3So 2 tan−1(2x1−x2) 

=π3Or   tan−1(2x1−x2) 

=π6So tan( tan−1(2x1−x2))

 =tanπ6Or 2x1−x2 

= 13√Or x2 +23√−1

=0Or x = −3√±2 

hope ans is helpful!!