tan- (1) 4x + tan-(1) 6x = π/4
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Step-by-step explanation:
Answer
tan
−1
4x+tan
−1
6x=
4
π
∵tan
−1
A+tan
−1
B=tan
−1
(
1−AB
A+B
)
∴tan
−1
(
1−24x
2
4x+6x
)=
4
π
⇒tan
−1
(
1−24x
2
10x
)=
4
π
⇒
1−24x
2
10x
=tan(
4
π
)⇒
1−24x
2
10x
=1⇒1−24x
2
=10x
⇒24x
2
+10−1=0⇒24x
2
+12x−2x−1=0
⇒12x(2x+1)−1(2x+1)=0⇒(12x−1)(2x+1)=0
⇒x=
2
−1
or x=
12
1
∵x=−
2
1
, LHS =tan
−1
(−2)+tan
−1
(−3) = negative
= RHS
∴
x=
12
1
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