tan^-1(cos(2/3)+sin(4/5))=???
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Answered by
2
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Answered by
0
Step-by-step explanation:
L
H
S
=
cos
(
tan
−
1
(
−
1
)
+
cos
−
1
(
−
4
5
)
)
=
cos
(
tan
−
1
tan
(
−
π
4
)
+
cos
−
1
(
−
4
5
)
)
=
cos
(
(
−
π
4
)
+
cos
−
1
(
−
4
5
)
)
=
cos
(
−
π
4
)
cos
(
cos
−
1
(
−
4
5
)
)
−
sin
(
−
π
4
)
sin
(
cos
−
1
(
−
4
5
)
)
=
cos
(
π
4
)
(
−
4
5
)
⎞
⎠
+
sin
(
π
4
)
sin
⎛
⎝
sin
−
1
√
1
−
(
−
4
5
)
2
⎞
⎠
=
1
√
2
×
(
−
4
5
)
+
1
√
2
×
3
5
=
−
4
+
3
5
√
2
=
−
1
5
√
2
=
−
√
2
10
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