Question

tan/1-cot+cot/1-tan=1+sec.cosec​

Answer 1

Answer:

Step-by-step explanation:

Taking LHS

Tan/1-cot +cot/1-tan

change cot into tan

tan/1-(1/tan)+(1/tan)/1-tan

tan²÷tan-1+1÷tan(1-tan)

1-tan³÷tan(1-tan)

(1-tan)(1+tan+tan²)÷tan(1-tan)(∵a³-b³)=(a-b)

sec²+tan÷tan(∵1+tan²=sec²)

1+sec²÷tan

1+1÷cos sin

1+sec ·cosec

=RHS

Hence proved