tan/1-cot+cot/1-tan=1+sec.cosec
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Answer:
Step-by-step explanation:
Taking LHS
Tan/1-cot +cot/1-tan
change cot into tan
tan/1-(1/tan)+(1/tan)/1-tan
tan²÷tan-1+1÷tan(1-tan)
1-tan³÷tan(1-tan)
(1-tan)(1+tan+tan²)÷tan(1-tan)(∵a³-b³)=(a-b)
sec²+tan÷tan(∵1+tan²=sec²)
1+sec²÷tan
1+1÷cos sin
1+sec ·cosec
=RHS
Hence proved
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